Question

efectueaza utilizand factorul comun 1999×2000-1998×1999-2×1998​ repede dau coroana

Answer 1

Salutare!!

$\bf 1999 \cdot 2000-1998 \cdot 1999-2 \cdot1998 =$

$\bf 1999 \cdot (2000-1998) -2 \cdot1998 =$

$\bf 1999 \cdot 2 -2 \cdot1998 =$

$\bf 2 \cdot (1999 - 1998)=$

$\bf 2 \cdot 1 =$

$\boxed{\bf 2 }$

==pav38==