Question

Energia potentiala a unui resort alungit 2 cm este egala cu 0,4J. Sa se calculeze constanta elastica. Multumesc mult

Answer 1

$x=2 cm=0,02 m\\E_{p_{el}}=\frac{kx^2}{2}<=>0,4=\frac{0,02^2k}{2}<=>0,4= \frac{0,0004k}{2}<=>0,4=0,0002k=>k=\frac{0,4}{0,0002}=2000 N/m\\k=2000N/m$