Question

Enuntul: Scrieti formula chimica a acidului azotic. Determinatil:
1. raportul atomic
2.raportul de masa
3.cate grame de azot se afla in 3 moli acid azotic
4. Masa acidului azotic in care se afla 96g O

Answer 1

HNO3
1. 1:1:3

2. H=1,N=1,O=3

H=1*1=1;N=1*14=14;O=3*16=48
H:N:O=1:14:48

3. M HNO3= 1+14+48=49+14=63
3=m/63=>m=63*3=189
63 grame HNO3......14 g N
189 grame HNO3.........x g N
=>x= (189*14)/63=42 g azot

4. 96 g Oxigen? hmm