Question

Este ecuația de la ex 2 , se poate vedea in poza

Answer 1

Bună!

$\frac{x}{3} -\frac{4-x}{2} =8\frac{5}{6} -\frac{x}{4} <=>^{4)} \frac{x}{3} -^{6)} \frac{4-x}{2} =^{2)} \frac{53}{6} -^{3)} \frac{x}{4} <=> 4x-6(4-x)=106-3x <=> 4x-24+6x=106-3x <=> 10x+3x=106+24 <=> 13x=130 => x=10$

• $8\frac{6}{5} =\frac{8*6+5}{6} =\frac{53}{6}$

Answer 2

$\it \dfrac{x}{3}-\dfrac{4-x}{2} =\dfrac{8\cdot6+5}{6}-\dfrac{x}{4}$

$\it \dfrac{x\cdot2}{6}-\dfrac{3\cdot4-3\cdot x}{6} =\dfrac{48+5}{6}-\dfrac{x}{4}$

$\it \dfrac{2x-12+3x}{6}} =\dfrac{53}{6}-\dfrac{x}{4}$

$\it \dfrac{5x-12}{6}} =\dfrac{53\cdot2}{12}-\dfrac{x\cdot3}{12}$

$\it \dfrac{5x-12}{6}} =\dfrac{106-3x}{12}}$

$\it 12\cdot(5x-12)=6\cdot(106-3x)\:\:\:|:6$

$\it 2\cdot5x-2\cdot12=106-3x$

$\it 10x-24=106-3x$

$\it 13x = 130$

$\it \boxed{\it x = 10}$

                  ꧁      Mult succes în continuare !  ꧂