Question

Este pentru TEZĂ.Va rog!!!

Answer 1

$a)a = {4}^{n} \times {3}^{2n + 1} - {2}^{2n} \times {9}^{n}$

$a = {2}^{2n} \times {3}^{2n + 1} - {2}^{2n} \times {3}^{2n}$

$a = {2}^{2n} \times {3}^{2n} (3 - 1)$

$a = {2}^{2n} \times {3}^{2n} \times 2$

$a = {2}^{2n + 1} \times {3}^{2n}$

$b)2a = 2 \times {2}^{2n + 1} \times {3}^{2n}$

$2a = {2}^{2n + 1 + 1} \times {3}^{2n}$

$2a = {2}^{2n + 2} \times {3}^{2n}$

$2a = {2}^{2(n + 1)} \times {3}^{2n}$

$2a = { ({2}^{n + 1}) }^{2} \times { ({3}^{n} )}^{2}$

$2a = { ({2}^{n + 1} \times {3}^{n} ) }^{2} =>p.p$