Question

este urgent dau coroana!!!!!​

Answer 1

Răspuns:

1

Rezolvare:

$\displaystyle \left[\left(-\frac{3}{5}\right)\cdot 2,5+\frac{5}{6}\right]:\frac{28}{42}+1,1+\frac{1}{10}\sqrt{81} =$

$\displaystyle = \left[\left(-\frac{3}{5}\right)\cdot \frac{25}{10}+\frac{5}{6}\right]:\frac{4}{6}+\frac{11}{10}+\frac{1}{10}\cdot 9$

$\displaystyle = \left[\left(-\frac{3}{5}\right)\cdot \frac{5}{2}+\frac{5}{6}\right]:\frac{4}{6}+\frac{11}{10}+\frac{9}{10}$

$\displaystyle = \left(-\frac{3}{2}+\frac{5}{6}\right):\frac{4}{6}+\frac{11+9}{10}$

$\displaystyle = \left(-\frac{3\cdot 5}{5\cdot 2}+\frac{5}{6}\right):\frac{4}{6}+\frac{20}{10}$

$\displaystyle = \left(-\frac{3}{2}+\frac{5}{6}\right):\frac{4}{6}+2$

$\displaystyle = \left(-\frac{9}{6}+\frac{5}{6}\right):\frac{4}{6}+2$

$\displaystyle =\frac{-9+5}{6}:\frac{4}{6}+2$

$\displaystyle =\frac{-4}{6}:\frac{4}{6}+2$

$\displaystyle =-\frac{4}{6}:\frac{4}{6}+2$

$=-1+2$

$\displaystyle = \boxed{1}$

Answer 2

Răspuns: $\purple{\bf ~1~}$

Explicație pas cu pas:

$\bf \Bigg[\bigg(-\dfrac{3}{5}\bigg)\cdot2,5+\dfrac{5}{6} \Bigg] :\dfrac{28}{42} +1,1+\dfrac{1}{10}\cdot\sqrt{81} =$

$\bf \bigg(-\dfrac{3}{\not5}\cdot\dfrac{\not25}{\not10} +\dfrac{5}{6}\bigg) :\dfrac{28}{42} +\dfrac{11}{10}+\dfrac{1}{10}\cdot\sqrt{9^{2}} =$

$\bf \bigg(-\dfrac{3}{1}\cdot\dfrac{1}{2} +\dfrac{5}{6}\bigg) \cdot\dfrac{42}{28} +\dfrac{11}{10}+\dfrac{1}{10}\cdot 9 =$

$\bf \bigg(-\dfrac{^{3)} 3~}{2} +\dfrac{5}{6}\bigg) \cdot\dfrac{~42^{(7} }{28} +\dfrac{11}{10}+\dfrac{9}{10} =$

$\bf \bigg(-\dfrac{9+5}{6} \bigg) \cdot\dfrac{6^{(2} }{4} +\dfrac{11}{10}+\dfrac{9}{10} =$

$\bf -\dfrac{~4^{(2}}{6} \cdot\dfrac{3 }{2} +\dfrac{20}{10} =$

$\bf -\dfrac{2}{3} \cdot\dfrac{3 }{2} +\dfrac{20^{(10}~}{10} =$

$\bf -\dfrac{6}{6} +2=$

$\bf -1 +2=$

$\red{\boxed{\bf ~1~}}$

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