Question

Ex. 1, 2, 3 rezolvate ....​

Answer 1

Răspuns:

a) -3x+1= x+13

-3x-x = 13-1

-4x= 12

x= 12÷(-4)

x= -3

b)

$2 \sqrt{2} x + \sqrt{8} = \sqrt{2} x + 3 \sqrt{2} \\ 2 \sqrt{2} x + \sqrt{4 \times 2} = \sqrt{2} x + 3 \sqrt{2} \\ 2 \sqrt{2} x + 2 \sqrt{2} = \sqrt{2} x + 3 \sqrt{2} \\ 2 \sqrt{2} x - \sqrt{2} x = 3 \sqrt{2} - 2 \sqrt{2} \\ \sqrt{2} x = \sqrt{2} \\ x = \frac{ \sqrt{2} }{ \sqrt{2} } = 1$