Question

ex:1 va rog mult sa ma ajutați

Answer 1

Bună!

$(\frac{2}{3}) ^{2} =\frac{2^{2} }{3^{2} } =\frac{4}{9}$

$(\frac{5}{2} )^{2} =\frac{5^{2} }{2^{2} } =\frac{25}{4}$

$(-\frac{1}{4} )^{2} =\frac{1^{2} }{4^{2} } =\frac{1}{16}$

$(-\frac{6}{7} )^{2} =\frac{6^{2} }{7^{2} } =\frac{36}{49}$

$0,5^{2} =(\frac{5}{10})^{2} =(\frac{1}{2}) ^{2}=\frac{1}{4}$

$0,1^{2} =(\frac{1}{10})^{2} =\frac{1^{2} }{10^{2} } =\frac{1}{100}$

$2,4^{2} =(\frac{24}{10} )^{2} =(\frac{12}{5} )^{2} =\frac{12^{2} }{5^{2} } =\frac{144}{25}$

$(-0,5)^{2} =-0,5*(-0,5)=0,25$

$(-1,2)^{2} =-1,2*(-1,2)=1,44$

$(-2,5)^{2} =-2,5*(-2,5)=6,25$