Question

Ex 10 va rog repede
Dau coroană ​

Answer 1

Răspuns:

a) $(2^{2})^{12}: (2^{2})^{14}= 2^{24} : 2^{28} = 2^{24-28}=2^{-4}=\frac{1}{2^{4} }=\frac{1}{16}$

b) $(5^{2})^{39} : (5^{3})^{25}=5^{78}:5^{75}= 5^{78-75}=5^3$$=125$

c)$(2^{2})^{12}* (2^{3})^{5}:(2^5)^7= 2^{24+15-35}=2^{39-34}=2^5=32$

Explicație pas cu pas: