Matematică, întrebare adresată de ImDenisaT, 9 ani în urmă

ex 11 !
de la b la j
dau coroana
urgent

Anexe:

Răspunsuri la întrebare

Răspuns de Fabianna02
1

B) B+149+[(9+7):4]=396

B+149+(16:4)=396

B+149+4=396

B+153=396

B=396-153

B=243

C) 93-(85-9*9+5*8)-c=5*6+1

93-(85-81+40)-c=31

93-(4+40)-c=31

93-44-c=31

49-c=31

C=49-31

C=18

D)(242+360:10-214):(80:5-4*2)*d=1000

(242+36-214):(16-8)*d=1000

(278-214):8*d=1000

64:8*d=1000

8*d=1000

d=1000:8

d=125

E)94+[(402:2+5*e)*2+8]:5=184

94+[(201+5*e)*2+8]:5=184

[(201+5*e)*2+8]:5=184-94

(201+5*e)*2+8=90:5

(201+5*e)*2=18-8

201+5*e=10:2

201+5*e=5

5*e=5-201

5*e=-196

e=-196:5

e=-39,2

F)500-[(16*18-192:f):7+14*5+10]:4*7+5=

=299

500-[(288-192:f):7+70+10]:4*7+5=299

[(288-192:f):7+70+10]:4*7+5=500-299

[(288-192:f):7+70+10]:4*7=201-5

[(288-192:f):7+70+10]:4=196:7

(288-192:f):7+70+10=28*4

(288-192:f):7+70=112-10

(288-192:f):7=102-70

288-192:f=32*7

192:f=288-224

f=192:64

f=3

G)6+[15-(8:a*7+7)]*5=8:(1*4)+3*3

6+[15-(8:a*7+7)]*5=8:4+9

6+[15-(8:a*7+7)]*5=2+9

6+[15-(8:a*7+7)]*5=11

[15-(8:a*7+7)]*5=11-6

15-(8:a*7+7)=5:5

15-(8:a*7+7)=1

8:a*7+7=15-1

8:a*7=14-7

8:a=7:7

a=8:1

a=8

H)4+4*[4+4*(4+h:4)+4]:4=52

4*[4+4*(4+h:4)+4]:4=52-4

[4+4*(4+h:4)+4]:4=48:4

4+4*(4+h:4)+4=12*4

4*(4+h:4)+4=48-4

(4+h:4)+4=44:4

4+h:4=11-4

h:4=7-4

h=3*4

h=12

I)834-[(6*137-364:i):7+139]:3=751

834-[(822-364:i):7+139]:3=751

[(822-364:i):7+139]:3=834-751

(822-364:i):7+139=83*3

(822-364:i):7=249-139

822-364:i=110*7

364:i=822-770

i=364:52

i=7

J)234+[(88:4+j)-78:6]*23=809

[(44+j)-13]*23=809-234

(44+j)-13=575:23

44+j=25+13

44+j=38

j=38-44

j=-6

Sper ca te am ajutat !!

Alte întrebări interesante