Question

ex 11 ....... mersiiiiiiii

Answer 1

   
[tex]\displaystyle \\ 11) \\ \text{Se da: } \\ \text{Triunghiul isoscel ABC} \\ AB = AC = 6~m \\ m(\ \textless \ BAC) = 150^o \\ \text{Se cere: } \\ A_{\Delta ABC} = ? \\ \\ \text{Rezolvare: } \\ \\ A = \frac{AB \times AC \times \sin 150^o}{2} = \\ \\ = \frac{6 \times 6 \times \sin (180^o-30^o)}{2} = \\ \\ = \frac{36 \times \sin (30^o)}{2} = \frac{36 \times \frac{1}{2} }{2} = \frac{36}{4} =\boxed{9~m^2}[/tex]