Question

EX 12 VA ROG MUUULTE PUNCTE

Answer 1

$\it m(\hat{C}) =180^o-(39^o+85^o)=180^o-124^o=56^o\\ \\ Unghiul\ exterior,\ din\ fiecare\ v\hat{a}rf,\ este\ suplementul\ unghiului\ interior.\\ \\ Unghiul\ exterior\ din\ A\ va\ avea\ m\breve{a}sura\ 180^o-39^o=141^o$

$\it Unghiul\ exterior\ din\ B\ va\ avea\ m\breve{a}sura\ 180^o-85^o=95^o\\ \\ Unghiul\ exterior\ din\ C\ va\ avea\ m\breve{a}sura\ 180^o-56^o=124^o$

Answer 2

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