Question

Ex 12 Vaaa rooog muult

Answer 1

apotema bazei =jumatare din latura
deci latura bazei mici = ap × 2 =9 × 2 =18 cm
deci latura bazei mari = aP × 2 =12 × 2 =24 cm

a) aria torala =(Pb+PB)×(ap trunchi /2)
Pb=perimetrul bazei mici =4 × 18 = 72 cm
PB= perimtrul bazei mari = 4 × 24 = 96 cm

deci Aria totala = (72 + 96) ×6/2
Aria totala =168 × 3 = 504 cm²

volum = h/3(Ab+AB+√(AB×Ab)
h² =ap trunchi² - (aP-ap)²=6² -(12-9)²
h=√(36-9)=√25
h = 5 cm
Ab =a²=18²=324
AB=b²=24²= 576
volum=(5/3)(324+576+√(576×324)
volum=(5/3)(900+432)
volum = (5/3)×1332=2220 cm³