Question

Ex 13! Dau coroana!!

Answer 1

$a) {x}^{2} + \frac{1}{2} x + \frac{1}{16} = {(x + \frac{1}{4}) }^{2}$

$b) \frac{9}{4} {x}^{2} - 3x + 1 = {( \frac{3}{2}x - 1) }^{2}$

$c) {x}^{2} + \frac{2}{5} x + \frac{1}{25} = {(x + \frac{1}{5} )}^{2}$

$d)5 {x}^{2} + 4 \sqrt{5} x + 4 = {( \sqrt{5}x + 2) }^{2}$

$e)7 {x}^{2} - 6 \sqrt{7} x + 9 = {( \sqrt{7} x - 3)}^{2}$

$f)2 {x}^{2} + 4 \sqrt{3} x + 6 = {( \sqrt{2}x + \sqrt{6}) }^{2}$