Matematică, întrebare adresată de davidstoica659, 8 ani în urmă

ex 13 pls dau coroană.​

Anexe:

Răspunsuri la întrebare

Răspuns de dariusbarbu
3

Răspuns:

Explicație pas cu pas:

a)

 \frac{7}{5}  + 1 \frac{1}{2}  +  \frac{3}{20}  - 2 \frac{1}{4}  \\

 =  \frac{7}{5}  +  \frac{1 \times 2 + 1}{2}  +  \frac{3}{20}  -  \frac{2 \times 4 + 1}{4}  \\

 =  \frac{ {}^{4)} 7}{5}  +  \frac{ {}^{10)} 3}{2}  +  \frac{3}{20}  -  \frac{ {}^{5)} 9}{4}  \\

 =  \frac{28 + 30  + 3 - 45}{20}  =  \frac{16 {}^{(4} }{20}  = \boxed{ \frac{4}{5}}  \\

b)

2 \frac{1}{4}  + 3 \frac{1}{5}  +  \frac{3}{20}  -  \frac{3}{10}  \\

 =  \frac{2 \times 4 + 1}{4}  +  \frac{3 \times 5 + 1}{5}  +  \frac{3}{20}  -  \frac{3}{10}  \\

 =  \frac{{5)}^9}{4}  +  \frac{{4)}^16}{5}  +  \frac{3}{20}  -  \frac{{2)}^3}{10}  \\

 =  \frac{45 + 64 + 3 - 6}{20}  =  \frac{106 {}^{(2} }{20}  =  \boxed{\frac{53}{10}  }\\

c)

4 \frac{13}{16}  - 2 \frac{1}{4}  + 1 \frac{3}{8}  \\

  = \frac{4 \times 16 + 13}{16}  -  \frac{2 \times 4 + 1}{4}  +  \frac{1 \times 8 + 3}{8}  \\

 =  \frac{77}{16}  -  \frac{ {}^{4)} 9}{4}  +  \frac{ {}^{2)} 11}{8}  \\

 =  \frac{77 - 36 + 22}{16}  =  \boxed{\frac{63}{16}}  \\

d)

 \frac{ {}^{4)} 11}{25}  -  \frac{7}{100}  +  \frac{ {}^{20)} 1}{5}  -  \frac{ {}^{5)} 3}{20}  \\

 =  \frac{44 - 7 + 20 - 15}{100}  =  \frac{42 {}^{(2} }{100}  =  \boxed{\frac{21}{50}}  \\

e)

 \frac{ {}^{4)} 5}{9}   +  \frac{ {}^{6)} 7}{6}  +  \frac{ {}^{9)} 9}{4}  +  \frac{6}{36}  \\

 =  \frac{20 + 42 + 81 + 6}{36}  =  \boxed{\frac{149}{36}}  \\

f)

 \frac{ {}^{2)} 7}{150}  +  \frac{ {}^{6)} 11}{50}  +  \frac{1}{300}  +  \frac{ {}^{3)} 23}{100}  \\

 =  \frac{14 + 66 + 1 + 69}{ 300}  =  \frac{150 {}^{(150} }{300}  =  \boxed{\frac{1}{2} } \\

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