Question

ex 13 plsss !!!! !!!!!!!!

Answer 1

${x}^{2} - 2x + {a}^{2} + 1 = 0$

$m= 1$

$n = - 2$

$p= {a}^{2} + 1$

$s = x_{1} + x_{2} = - \frac{n}{m} = - \frac{ - 2}{1} = 2$

$p = x_{1} x_{2} = \frac{p}{m} = \frac{ {a}^{2} + 1 }{1} = {a}^{2} + 1$

$2x_{1} + 2x_{2} + x_{1}x_{2} = 9$

$2(x_{1} + x_{2}) + x_{1}x_{2} = 9$

$2s + p = 9$

$2 \times 2 + {a}^{2} + 1 = 9$

$4 + {a}^{2} + 1 = 9$

${a}^{2} = 9 - 4 - 1$

${a}^{2} = 4$

$a = \pm \sqrt{4}$

$a = \pm2$