Question

ex 15 va rog sa ma ajutati Ex ala cu Determina......​

Answer 1

Răspuns:

{[(x-8)×7+6-5]-4}×3-2=10

{[(x-8)×7+6-5]-4}×3=10+2

{[(x-8)×7+6-5]-4}×3=12

{[(x-8)×7+6-5]-4}=12÷3

{[(x-8)×7+6-5]-4}=4

[(x-8)×7+6-5]=4+4

[(x-8)×7+6-5]=8

[(x-8)×7+6]=8+5

[(x-8)×7+6]=13

[(x-8)×7]=13-6

[(x-8)×7]=7

x-8=7÷7

x-8=1

x=8+1

x=9