Matematică, întrebare adresată de mirela200222, 9 ani în urmă

Ex 16 dau 55 pcte repede va rog

Anexe:

cocirmariadenis: La subpunctu c, nu se vede puterea = 2/5 ?

Răspunsuri la întrebare

Răspuns de Utilizator anonim
5
(3/4)^6:(3/4)^4=(3/4)^6-4=(3/4)^2=9/16 --- A

(1/2)^8:(1/2)^4=(1/2)^8-4=(1/2)^4=1/16 --- F

(2/5)^10:(2/5)^10= 1 --- F

(1/3)^6:(1/3)^1=(1/3)^6-1=(1/3)^5=1/243 --- F

(3/2)^6:(3/2)^6=1 --- A

(5/6)^20:(5/6)^18=(5/6)^20-18=(5/6)^2=25/36 --- A

(10/3)^30:(10/3)^27=(10/3)^30-27=(10/3)^3=1000/27 --- F

(1/20)^6:(1/20)^3=(1/20)^6-3=(1/20)^3=1/8000 ---F

(3/5)^7:(3/5)^2=(3/5)^7-2=(3/5)^5=243/3125 --- F

mirela200222: Mese
Utilizator anonim: Cu plăcere!
Răspuns de cocirmariadenis
2
a) ( 3/4)⁶ : ( 3/4)⁴ = (3/4)⁽⁶⁻⁴⁾ = ( 3/4)² = 3²/4²= 9/16 = 9/16 (Adevarat)

b) (1/2)⁸ : ( 1/2)⁴ = ( 1/2)⁽⁸⁻⁴⁾= (1/2)⁴=1⁴/2⁴=1/16 =1/4 (fals)

c) (2/5)¹⁰ : ( 2/5)¹⁰= ( 2/5)⁽¹⁰⁻¹⁰⁾=(2/5)⁰ = 1=2/5 ( fals)

d) (1/3)⁶ : (1/3)¹= (1/3)⁽⁶⁻¹⁾=(1/3)⁵=1⁵/3⁵= 1/243= 1/27 ( fals)

e)  ( 3/2)⁶ : ( 3/2)⁶ = ( 3/2)⁽⁶⁻⁶⁾= (3/2)⁰ = 1/1 = 1  (Adevarat)

f)  ( 5/6)²⁰ : ( 5/6)¹⁸ = ( 5/6)⁽²⁰⁻¹⁸⁾= ( 5/6)²= 5²/6²=25/36 (Adevarat)

g)  ( 10/3)³⁰: (10/3)²⁷=(10/3)⁽³⁰⁻²⁷⁾= (10/3)³=10³/3³=1 000/27 = 100/9 (Fals)

h)  ( 1/20)⁶ : ( 1/20)³= (1/20)⁽⁶⁻³⁾=(1/20)³=1³/20³=1/8000 = 1/400 ( Fals)

i) ( 3/5)⁷: ( 3/5)²=(3/5)⁽⁷⁻²⁾=(3/5)⁵= 3⁵/5⁵= 243/3125 = 81/625 (Fals)
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