Question

Ex.18va rog mult.Sa fie corect.Multumesc

Answer 1

a. (2√2+3√3)/√6 · √3-(√8-√12)/(√8·√12) · √24=
= (2√2+3√3)/√2 - (√8-√12)/2=
=(2√2+3√3)/√2-2(√2-√3)/2=
=(4+3√6)/2-(2√2-2√3)/2=
=(4+3√6-2√2+2√3)/2
b. numitor comun √60
(√12-√30)/√60+(√30-√15)/√60-(2√3-√15)/√60=
=(2√3-√30+√30-√15-2√3+√15)/√60=
=0
c. numitor comun √60
(√20-√30)/√60 + (√15-√20)/√60 +(√12 - √15)/√60 + (√10-√12)/√60=
=(√20-√30+√15-√20+√12-√15+√10-√12)/√60=
=(√10-√30)/√60=
=√10(1-√3)/√60=
=(1-√3)/√6=(√6-3√2)/6=√2(√3-3)/6
d. 2√5(√3+1)/2-3√3(√5+2)/3=
=√5(√3+1)-√3(√5+2)=
=√15+√5-√15-2√3=
=√5-2√3