Question

ex 2,3,4 va rooog rapid

Answer 1

2. m Cu impur = 20g

m Cu pur = 20-2,5=17,5g

puritatea = m pur / m impur *100 = 17,5/20*100=87,5%

3. puritatea = V pur / V impur *100 => V pur = p*V impur/100=97*200/100=194 L CH4 pur

puritatea = 97%

4. ms1 = 500g
C1=10%

C1=md1/ms1*100=>md1=Cp1*ms1/100=10*500/100=50g NaOH

md2=20g

md final = md1 + md2 = 50+20=70g

ms final = ms1 + md2 = 500+20 = 520g

C final = mdf/msf*100=70/520*100=13,4615%