Question

Ex 2&3 plssss dau coroană

Answer 1

$2)A = {( {3}^{2}) }^{4} \div {3}^{6} \times {3}^{2}$

$A = {3}^{2 \times 4} \div {3}^{6} \times {3}^{2}$

$A = {3}^{8} \div {3}^{6} \times {3}^{2}$

$A = {3}^{8 - 6 + 2}$

$A = {3}^{2 + 2}$

$A = {3}^{4}$

$A = 81$

$B = 8 \times {10}^{2} + 0 \times 10 + 1 \times {10}^{0}$

$B = 8 \times 100 + 0 + 1 \times 1$

$B = 800 + 1$

$B = 801$

$81 < 801 = > A < B$

$2)1 + 2 + 3 + ... + 49 = \frac{49(49 + 1)}{2} = \frac{49 \times 50}{2}$

$= 49 \times 25 = {7}^{2} \times {5}^{2} = {(7 \times 5)}^{2} = {35}^{2} = > p.p$