Question

Ex 2 (cel care e incercuit)

Answer 1

a) transformam in fractii fiecare termen: 
    0,xy(z)=(xyz-xy)/900
    0,yz(x)=(yzx-yz)/900
    0,zx(y)=(zxy-zx)/900
scrise in baza 10 avem:
   (100x+10y+z-10x-y)/900 +(100y+10z+x-10y-z)/900+(100z+10x+y-10z-x)/900=
(111x+111y+111z-11x-11y-11z)/900=100(x+y+z)/900
√100(x+y+z)/900 pentru a fi numar natural trebuie sa fie patrate perfecte
deci (x+y+z)= 100