Question

ex 2 plsssss va roggggg

Answer 1

$\displaystyle a= \left| \sqrt{3} -2 \right|-\left(2+ \sqrt{3} \right) \\ \\ a=2- \sqrt{3} -2- \sqrt{3} \\ \\ a=-2 \sqrt{3} \\ \\ b= \frac{1}{2+ \sqrt{3} } - \frac{1}{2- \sqrt{3} } \\ \\ b= \frac{2- \sqrt{3}-\left(2+ \sqrt{3} \right) }{4-3} \\ \\ b=2- \sqrt{3} -2- \sqrt{3} \\ \\ b=-2 \sqrt{3} \\ \\ -2 \sqrt{3} =-2 \sqrt{3} \Rightarrow a=b$