Question

ex 2 rezolvare va rog mult ca nu il stiu rezolva

Answer 1

$\it3^{100}\cdot[3^{2^7}-(3^4)^{32}]:3^{2020}=3^{100}\cdot(3^{128}-3^{128});3^{2020}=3^{100}\cdot0:3^{2020}=0$

Answer 2

Răspuns:

=>>> ${3}^{100} \times ( {3}^{ {2}^{7} } -( {3}^{4} ) ^{32} ) \div {3}^{2020} = 0 \\ {3}^{2 ^{7} } = {3}^{128 } \\ ({3}^{4} )^{32} = {3}^{128} \\ {3}^{100} \times ( {3}^{128} - {3}^{128} ) \div {3}^{2020} = \\ {3}^{100} \times 0 \div {3}^{2020} = 0 \div {3}^{2020} = 0$