Question

ex 2 va rog este urgentt!¡¡​

Answer 1

   

$\displaystyle\bf\\2)\\a)\\0,\!(3)=\frac{1}{3}\\\\1,\!(3)=1+0,\!(3)=1+\frac{1}{3}=\frac{4}{3}\\\\Ponderile~sunt~3~si~9\\\\m_{ap}=\frac{\dfrac{1}{3}\times3+\dfrac{4}{3}\times9}{3+9}=\frac{1+12}{3+9} =\frac{13}{12}=\boxed{\bf1\frac{1}{12}}\\\\\\b)\\\\ m_{ap}=\frac{\dfrac{2}{3}\times12+\dfrac{1}{2}\times8+\dfrac{4}{7}\times28}{12+8+28}=\frac{8+4+16}{12+8+28}=\frac{28}{48}=\boxed{\bf\frac{7}{12}}$