Question

ex.2 va rog urgent, dau coronita

Answer 1

$a)5 |x + 3| = 6 - 7 |x + 3|$

$5 |x + 3| + 7 |x + 3| = 6$

$|x + 3| (5 + 7) = 6$

$12 |x + 3| = 6 \: | \div 6$

$2 |x + 3| = 1$

$|x + 3| = \frac{1}{2}$

$1)x + 3 = \frac{1}{2}$

$x = \frac{1}{2} - 3$

$x = \frac{1}{2} - \frac{6}{2}$

$x = - \frac{5}{2}$

$2)x + 3 = - \frac{1}{2}$

$x = - \frac{1}{2} - 3$

$x = - \frac{1}{2} - \frac{6}{2}$

$x = - \frac{7}{2}$

$b) |x + 1| = |2x - 2|$

$1)x + 1 = 2x - 2$

$x - 2x = - 2 - 1$

$- x = - 3 \: | \times ( - 1)$

$x = 3$

$2) - (x + 1) = 2x - 2$

$- x - 1 = 2x - 2$

$- x - 2x = - 2 + 1$

$- 3x = - 1 \: | \times ( - 1)$

$3x = 1$

$x = \frac{1}{3}$

$3)x + 1 = - (2x - 2)$

$x + 1 = - 2x + 2$

$x + 2x = 2 - 1$

$3x = 1$

$x = \frac{1}{3}$

$4) - (x + 1) = - (2x - 2)$

$- x - 1 = - 2x + 2$

$- x + 2x = 2 + 1$

$x = 3$