Question

ex 23 si 24 repede va rog cu rezolvare completa,repede va rog

Answer 1

a)[43-(37*35+24)/35]-[25/14-4/14]=

[tex] \frac{43*35-37*35+24}{35} - \frac{25-4}{14} [/tex]=

=$\frac{35*6+24}{35} - \frac{19}{14}$

aduc la acelasi numitor care este 70, amplific prima fractie cu 2 si a doua cu 5

=$\frac{35*12+48}{70} - \frac{95}{70}$

(420-47)/70=373/70

b.  $\frac{99*26+11}{26} - (\frac{71*13+13}{13} - \frac{23*26+7}{26} )=$

$\frac{99*26+11}{26} - ( \frac{142*13+6}{26} - \frac{23*26+7}{26} )$

[2585-(1846+6-598-7)]/26=(2585-1247)/26=1338/26

24. a. $\frac{23*4-19*4-1}{4} + \frac{3}{5} - ( \frac{7}{3} - \frac{19}{24} ) =$

Numitorul comun e 120, amplific prima fractie cu 30, a doua cu 24, a treia cu 40 si ultima cu 5

$\frac{15*30}{120} + \frac{72}{120} - \frac{280}{120} - \frac{95}{120} = \frac{147}{120}$

b. $\frac{12*90+29}{90} + [ \frac{28}{3} + \frac{35}{6} - \frac{133}{9} - (\frac{361}{72} - \frac{221}{72} )]$

$\frac{1109*4}{360} + \frac{28*120}{360} + \frac{35*60}{360} - \frac{133*40}{360} - \frac{140*5}{360}$

$\frac{4436+3360+2100-5320-700}{360} = \frac{3876}{360}$