Question

ex 24\pag 18 a si b. va rog

Answer 1

a)√(28-10√3)+√(5-2√6)+√(18+8√2)=

se folosește descompunerea in factori

√a²±2ab+b²=√(a±b)²

5-√3+√3-√2+ 4+√2=9

x-2=±1. x1=3. x2=1

x-2=±9

x3=11. x4 =-7

x-2=±3

x5=5. x6=-1

A={-7;-1;1;3;5;11}

b)√(10-2√21)+√(39+12√3)+√(16-6√7)=

√7-√3+6+√3+3-√7=6

2x+1=±1

x1=0 x2=-2/2=-1

2x+1=±3

x3=2/2=1. x4=-4/2=-2

2x+1=±2

x5=1/2 nu. x6=-3/2 nu

2x+1=±6

x7=5/2 nu x8=-7/2 nu

B={-2;-1;0;1}