Question

ex 24
urgeeeent
dau coroana!!!!

Answer 1

24.a)$\sqrt{32 a^{3} b^{10} }= \sqrt{ 2^{5} a^{3} b^{10} } =-4a b^{5} \sqrt{2a}$  ,e cu minus deoarece b<0
b)$\sqrt{27(a-b)}= \sqrt{ 3^{3}(a-b) } =3 \sqrt{3(a-b)}$
c)$\sqrt{-8(a-3)^{3}} = \sqrt{- 2^{3}(a-3)^{3} }=2 \sqrt{2(a-3)^{3}} , (a\ \textless \ 3)$
d)nu vad puterile numerelor :(
Sper sa te fi ajutat!