Question

Ex 25. Urgent!!! Dau 100 de puncte!

Answer 1

$\it x=\dfrac{\sqrt3+\sqrt5 +\sqrt6+\sqrt7+\sqrt{10}+\sqrt{14}}{\sqrt3+\sqrt5 +\sqrt7}=\dfrac{\sqrt3+\sqrt5 +\sqrt7}{\sqrt3+\sqrt5 +\sqrt7}+\dfrac{\sqrt6+\sqrt{10}+\sqrt{14}}{\sqrt3+\sqrt5 +\sqrt7}=\\ \\ \\ =1+\dfrac{\sqrt2(\sqrt3+\sqrt5 +\sqrt7)}{\sqrt3+\sqrt5+\sqrt7}=1+\sqrt2 > 1+1=2\\ \\ \\ A\d s adar,\ \ x > 2\ \Rightarrow num\breve a rul\ cerut\ este\ egal\ cu\ 2\ .$