Question

Ex.3

200 ml sieop de zahar de 70% contine ........ g de zahar.

50 ml solutie de sare de 20% contine ........ g de sare.

100 ml tinctura de iod de 5% contine ........ g se iod.

Ex.4

a) in numar zecimal

15%=?

110%=?

1,7%=?

b) in procente

0,36=?

3/20=?

5/4=?

Answer 1

Răspuns:

Explicație pas cu pas:

3. 200x70/100 = 140 g zahar

50 x 20/100 = 5 x 2 = 10 g sare

100 x 5/100 = 5 g iod

-----------------------------------

4.a. 15/100=0,15

110/100=1,10

17/100 =0,017

b. 0,36 = 36%

3/20 = 15/100 = 15%

5/4 = 125/100 = 125%

Answer 2

Răspuns:

Explicație pas cu pas:

3.

70%×200=7/100 × 200=140 g sare

20%×50=20/100 × 50=10 g sare

5%×100=5/100 × 100= 5 g iod

4.

a) 15%=15/100=0.15

110%=110/100=1.1

1.7%=17/10 × 100=17/1000=0.017

b) 0,36=36/100=36%

3/20 =15%

5/4=1,25=125%