Question

Ex 3, c)
Ma puteti ajuta, va rog?:D

Answer 1

C3H8+7/2O2---> 3CO2+4H2O        ori 1a moli

C4H10+13/2O2---> 4CO2+5H2O     ori 2a moli

V,O2= V,aer/5= 806,4 l----> niu,O2= V/Vm= 806,4/22,4 mol= 36mol

din ecuatii:  36= (3,5a+ 6,5x2a)----> a= 2,18mol

V, hidrocarburi= (2,18+2x2,18)molx22,4l/mol=.................calculeaza

procentul volumetric=procentul molar

niuCO2= 11a mol.....niuH2O= 14a mol---> total 25a mol

25a mol gaze.......11a molCO2..........14a mol H2O

100mol.................x............................y..............................calculeaza x  si  y !!!!!