Question

Ex 38/37( problemar)
Calculați:
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Answer 1

Răspuns:

Explicație pas cu pas:

a)

$|2-\sqrt{3} | + |1-\sqrt{3} | = 2-\sqrt{3} + \sqrt{3} - 1 = 1$

b)

$|2-\sqrt{3} | +|\sqrt{5} +\sqrt{3} |+ |\sqrt{3}-2 | = 2-\sqrt{3} + \sqrt{5} +\sqrt{3} + 2-\sqrt{3} =4 + \sqrt{5} -\sqrt{3}$

c)

$|\sqrt{2}+3 | + |\sqrt{2}-3 | = \sqrt{2}+3 + 3-\sqrt{2} = 6$

d)

$2\sqrt{3} -3\sqrt{2} +2*|\sqrt{3}-2|+3*|\sqrt{2}-1| = \\2\sqrt{3} -3\sqrt{2} +2*(2-\sqrt{3})+3*(\sqrt{2}-1) = \\=2\sqrt{3} -3\sqrt{2} +4-2\sqrt{3}+3\sqrt{2}-3 = 1$