Ex 4 dau coroana
Ajutor
Anexe:
Răspunsuri la întrebare
Răspuns de
2
a) 45×(16+25)=45×41=1845
b)121÷(45×10-439)=121÷(450-439)=121÷11=11
c)[(314÷2-57)+25]÷25-5=(100+25)÷25-5=125÷25-5=5-5=0
g)48×(2×9-2×3 la puterea 2)=48×(18-2×9)=48×(18-18)=48×0=0
h) 7la puetrea 2×(27 la puterea 3÷9 la puterea4+1)=49×(19683÷6561)=49×3=147
d){[(120+2×15)÷75+4]×10 la puterea 2-40×5}÷80={[(120+30)÷75+4]×100-40×5}=[(150÷75+4)×100-40×5]=[(2+4)×100-40×5]=(6×100-40×5)=600-200=300
b)121÷(45×10-439)=121÷(450-439)=121÷11=11
c)[(314÷2-57)+25]÷25-5=(100+25)÷25-5=125÷25-5=5-5=0
g)48×(2×9-2×3 la puterea 2)=48×(18-2×9)=48×(18-18)=48×0=0
h) 7la puetrea 2×(27 la puterea 3÷9 la puterea4+1)=49×(19683÷6561)=49×3=147
d){[(120+2×15)÷75+4]×10 la puterea 2-40×5}÷80={[(120+30)÷75+4]×100-40×5}=[(150÷75+4)×100-40×5]=[(2+4)×100-40×5]=(6×100-40×5)=600-200=300
antoniapo:
Imd
Răspuns de
1
a)45×(16+25)=45×41=1846
b)121:(45×10-439)=121:(450-439)=121:11=11
c)[(314:2-57)+25]:25-5=[(157-57)+25]:25-5=(100+25):25-5=125:25-5=5-5=0
d){[(120+2×15)×75+4]×10^2-40×5}:80={[(120+30):75+4]×10^2-200}:80=[(150:75+4)×10^2-200]:80=[(2+4)×10^2-200]:80=(6×10^2-200):80=(6×100-200):80=400:80=5
e) (asta ti.am scris )
f)4500-5×450-5×(5^55:25^27+10^2:4)×(1×2^2×3^3-3×6^2+7):42=4500-2250-5×(5^55:(5^2)^27+10^2:4)×(1×4×27-3×36+7):42=4500-2250-5×(5^55:5^(2×27)+100:4)×(4×27-108+7):42=4500-2250-5×(5^55×5^54+100:4)×(108-108+7):42=4500-2250-5×(5^1+100:4)×(0+7):42=4500-2250-5×(5+25)×7:42=4500-2250-5×30×7:42=2250-150:7:42=2250-1050:42=2250-25=2225
g)48×(2×9-2×3^2)=48×(18-2×9)=48×(18-18)=48×0=0
h)7^2×(27^3:9^4+1)=49×((3^3)^3:(3^2)^4+1=49×(3^9:3^8+1)=49×(3^1+1)=49×4=196
i)74:(2017^2017+2017^0+0^2017)^0= 74:1=74
j)4×[23+5×(23-4×2^2)]+2017^0=4×[23+5×(23-4×4)]+1=4×[23+5×(23-16)]+1=4×(23+5×7)+1=4×(23+35)+1=4×58+1=232+1=233
k)2^0+5×(5^100+5^99+5^98):5^98+343:7^2=1+5×(5^99+5^1+5^98+5^1+5^98):5^98+343:49=
(nu mai pot face acum, dar sper sa îmi termin ce am de facut si incerc sa le rezolv si pe ultimele 2 )
sper ca te-am ajutat !
b)121:(45×10-439)=121:(450-439)=121:11=11
c)[(314:2-57)+25]:25-5=[(157-57)+25]:25-5=(100+25):25-5=125:25-5=5-5=0
d){[(120+2×15)×75+4]×10^2-40×5}:80={[(120+30):75+4]×10^2-200}:80=[(150:75+4)×10^2-200]:80=[(2+4)×10^2-200]:80=(6×10^2-200):80=(6×100-200):80=400:80=5
e) (asta ti.am scris )
f)4500-5×450-5×(5^55:25^27+10^2:4)×(1×2^2×3^3-3×6^2+7):42=4500-2250-5×(5^55:(5^2)^27+10^2:4)×(1×4×27-3×36+7):42=4500-2250-5×(5^55:5^(2×27)+100:4)×(4×27-108+7):42=4500-2250-5×(5^55×5^54+100:4)×(108-108+7):42=4500-2250-5×(5^1+100:4)×(0+7):42=4500-2250-5×(5+25)×7:42=4500-2250-5×30×7:42=2250-150:7:42=2250-1050:42=2250-25=2225
g)48×(2×9-2×3^2)=48×(18-2×9)=48×(18-18)=48×0=0
h)7^2×(27^3:9^4+1)=49×((3^3)^3:(3^2)^4+1=49×(3^9:3^8+1)=49×(3^1+1)=49×4=196
i)74:(2017^2017+2017^0+0^2017)^0= 74:1=74
j)4×[23+5×(23-4×2^2)]+2017^0=4×[23+5×(23-4×4)]+1=4×[23+5×(23-16)]+1=4×(23+5×7)+1=4×(23+35)+1=4×58+1=232+1=233
k)2^0+5×(5^100+5^99+5^98):5^98+343:7^2=1+5×(5^99+5^1+5^98+5^1+5^98):5^98+343:49=
(nu mai pot face acum, dar sper sa îmi termin ce am de facut si incerc sa le rezolv si pe ultimele 2 )
sper ca te-am ajutat !
Alte întrebări interesante
Limba română,
8 ani în urmă
Limba română,
8 ani în urmă
Limba română,
9 ani în urmă
Matematică,
9 ani în urmă
Limba română,
9 ani în urmă