Question

ex 4 va rog ,dau 100 de puncte + coroana​

Answer 1

Explicație pas cu pas:

a)

$\dfrac{^{6)} 3}{2 \sqrt{2} } - \dfrac{^{4)}2}{3 \sqrt{2} } + \dfrac{^{2)}1}{6 \sqrt{2} } - \dfrac{^{3)}2}{4 \sqrt{2} } = \dfrac{18 - 8 + 2 - 6}{12 \sqrt{2} } = \dfrac{6 ^{(6} }{12 \sqrt{2} } = \dfrac{^{ \sqrt{2})}1 }{2 \sqrt{2} } = \dfrac{ \sqrt{2} }{4}$

b)

$\dfrac{8}{\sqrt{2} } - \dfrac{12^{(3}}{3 \sqrt{2} } + \dfrac{10^{(5}}{5 \sqrt{2} } - \dfrac{24^{(6}}{6 \sqrt{2} } = \dfrac{8}{\sqrt{2} } - \dfrac{4}{ \sqrt{2} } + \dfrac{2}{ \sqrt{2} } - \dfrac{4}{ \sqrt{2} } = \dfrac{8 - 4 + 2 - 4}{ \sqrt{2} } = \dfrac{^{ \sqrt{2} )} 2}{ \sqrt{2} } = \dfrac{2 \sqrt{2} }{2} = \sqrt{2}$

c)

$\dfrac{27^{(3}}{3 \sqrt{3} } - \dfrac{10^{(5}}{5 \sqrt{3} } + \dfrac{16^{(2}}{2 \sqrt{3} } - \dfrac{3}{ \sqrt{3} } = \dfrac{9}{ \sqrt{3} } - \dfrac{2}{ \sqrt{3} } + \dfrac{8}{ \sqrt{3} } - \dfrac{3}{ \sqrt{3} } = \dfrac{9 - 2 + 8 - 3}{ \sqrt{3} } = \dfrac{^{ \sqrt{3} )} 12}{ \sqrt{3} } = \dfrac{12 \sqrt{3}^{(3} }{3} = 4 \sqrt{3}$

d)

$\dfrac{^{6)}3}{2 \sqrt{6} } - \dfrac{^{4)}4}{3 \sqrt{6} } - \dfrac{^{3)}7}{4 \sqrt{6} } + \dfrac{^{2)}5}{6 \sqrt{6} } = \dfrac{18 - 16 - 21 + 10}{12 \sqrt{6} } = - \dfrac{^{ \sqrt{6} )} 9}{12 \sqrt{6} } = - \dfrac{9 \sqrt{6}^{(9} }{72} = - \dfrac{ \sqrt{6} }{8}$