Question

ex 5 va rog lamurițimi ce se da ca nu pot intelege, ajutațimaaa pls

Answer 1

MCO2=44g/mol

In 44g CO2 se gasesc 12g C
In 3,95g CO2...............x=1,07727g C

MH2O=18g/mol

In 18g H2O se gasesc........2gH2
In 2,44g H2O.....................x=0,27(1)g H2

mO=2,05-1,07727-0,27(1) = 0,70161g O

n=m/M=1,07727/12=0,0897725 moli C ||:0,04385 => 2 atomi C

n=m/M=0,27(1)/2=0,13555 moli H2 => 6 atomi H

n=m/M=0,70161/16=0,04385 moli O => 1 atom O

Formula moleculara => C2H6O -etanolul sau alcoolul etilic