Question

ex 5 va rog mult! dau coroana si 20 de puncte

Answer 1

Răspuns:

a) (x-4)^2 = x^2-2*x*4+4^2 = x^2-8x+16

b) (y-1)^2=y^2-2*y*1+1^2=y^2-2y+1

c) (3y-2)^2=(3y)^2-2*3y*2+2^2=9y^2-12y+4

d)(1-3a)^2=1^2-2*1*3a+(3a)^2=1-6a+9a^2

e)(3-5b)^2=3^2-2*3*5b+(5b)^2=9-30b+25b^2

f)(3x-7)^2=(3x)^2-2*3x*7+7^2=9x^2-42x+49

g)(4x-3)^2=(4x)^2-2*4x*3+3^2=16x^2-24x+9

h)(x^3-x)^2=(x^3)^2-2*x^3*x+x^2=x^6-2x^4+x^2

i)(x^2-x^5)^2=(x^2)^2-2*x^2*x^5+(x^5)^2=x^4-2x^7+x^10

j)(3x-7x^2)^2=(3x)^2-2*3x*7x^2+(7x^2)^2=9x^2-42x^3+7x^4

k)(y^2-2y)^2=(y^2)^2-2*y^2*2y+(2y)^2=y^4-4y^3+4y^2

l)(3a^4-a^2)^2=(3a^4)^2-2*3a^4*a^2+(a^2)^2=9a^8-6a^6+a^4

^ -inseamna ca ridic la putere iar * inmultire

Sper sa fie corect ,daca e ceva gresit da-mi mesaj..Incearca pe viitor sa faci o poza mai clara e posibil sa fi gresit la calcul si din cauza pozei care e putin neclara ..

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