Question

EX. 5 va rog nu prea am inteles

Answer 1

E(x)=[(x-3)/(x²-x-6) × (4x+8)/(x-1)+3] × (x-1)/(6x+2)=
=[(x-3)/(x²+2x-3x-6) × 4(x+2)/(x-1)+3] × (x-1)/2(3x+1)=
=[(x-3)/(x+2)(x-3) × 4(x+2)/(x-1)+3] × (x-1)/2(3x+1)=
=[1/1 × 4/(x-1)+3] × (x-1)/2(3x+1)=
=4/(x-1) × (x-1)/2(3x+1)=
=(4+3x-3)/(x-1) × (x-1)/2(3x+1)=
=(4+3x-3)/1 × 1/2(3x+1)=
=(3x+1) × 1/2(3x+1)=
=1/2