Question

Ex. 523 !!!
Repede va rog frumos!!
Urgent!!!

Answer 1

[(X+780:6)x 3+4]x 5=1985

Notam adunarea ,,X+780'' cu Y:
[(Y:6)x 3+4]x 5=1985
   
Notam inmultirea ,,Y:6'' cu Z:
(Z x 3+4)x 5=1985
Z x 3+4=1985:5
Z x 3+4=397
Z x 3=397-4
Z x 3=393
Z=393:3
Z=131
Y:6=Z
Y:6=131
Y=131 x 6
Y=786
X+780=Y
X+780=786
X=786-780
X=6

(y:2-5)x 3-91:7=2

Notam impartirea ,,y:2'' cu A:
(A-5)x 3-91:7=2

Notam scaderea ,,A-5'' cu B:
B x 3-91:7=2
B x 3-13=2
B x 3=2+13
B x 3=15
B=15:3
B=5
A-5=B
A-5=5
A=5+5
A=10
y:2=A
y:2=10
y=10 x 2
y=20


X=6 si y=20,deci X<y(X este mai mic fata de y)

Answer 2

[(x+780:6)*3+4]*5=1985
[(x+780:6)*3+4]=1985:5
[(x+780:6)*3+4]=397
[(x+780:6)*3]=397-4
[(x+780:6)*3]=393
[(x+780:6)]=393:3
(x+780:6)=131
(x+780)=131*6
(x+780)=786
x=786-780
x=6


(y:2-5)*3-91:7=2
(y:2-5)*3-91=2*7
(y:2-5)*3-91=14
(y:2-5)*3=14+91
(y:2-5)*3=105
(y:2-5)=105:3
(y:2-5)=35
(y:2)=35+5
(y:2)=40
y=40:2
y=20


x=6      y=20
6<20       x<y