Question

ex 6 si 7 ajutor
:) dau coronita
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Answer 1

Răspuns:

Explicație pas cu pas:

6. a. f(x)=-x-5

A(3m, 2m-9) ∈ Gf ⇔ f(3m)=2m-9

-3m-5=2m-9, 5m=4, m=4/5

b.

$f(\sqrt{2})= -\sqrt{2}-5\\ f(-\sqrt{2})=\sqrt{2}-5$

$m_{a}=\frac{-\sqrt{2}-5+\sqrt{2}-5 }{2}=\frac{-10}{2}=-5$

$m_{g}=\sqrt{(-\sqrt{2}-5 )(\sqrt{2}-5 )} =\sqrt{23}$

7.

f(x)=-3x+2

f(2x)=-6x+2, f(-1)=5, f(-x)=3x+2, f(2/3)=0

$\frac{-3x+2+4}{2}+5=3x+2$

-3x+6+10=6x+4

9x=12, x=4/3