Question

Ex. 6 si 7 vă rog frumos depinde de media mea la matematică

Answer 1

Răspuns:

6. a) $\frac{14}{27} * \frac{3}{2*3+2} * (- \frac{15}{7})$ = $\frac{2}{9} *\frac{1}{8} * (-\frac{5*3}{1} )$= $-\frac{5}{12}$

b) $\frac{18*1+7}{18} * (-\frac{9}{5}) *\frac{16}{35}$= - $\frac{5}{2}$  * $\frac{16}{35}$= - $\frac{8}{7}$

c) $\frac{12}{49} *\frac{14}{14*1+1} * \frac{7*3}{2*10}$= $\frac{12*2*3}{3*5*2*10}$= $\frac{3}{25}$

d) $\frac{8}{5*5} * \frac{3*5}{15*3+11} * \frac{4*7}{3*3}$= $\frac{3*4*7}{5*7*3*3}$= $\frac{4}{15}$

e) ($- \frac{27*1+13}{27} )$ * $\frac{9}{20} * \frac{3*7}{2*5}$= -  $\frac{2*20* 3*7}{3*20*2*5}$ = $- \frac{7}{5}$

7. a)  $\frac{16}{10} * \frac{9}{17-1}$= $\frac{9}{10}$   b) $\frac{53-5}{9} * \frac{10}{3*8}$= $\frac{6*8*2*5}{9*3*8}$=$\frac{20}{9}$

c) $\frac{25}{10} * \frac{9}{16-1}$= $\frac{5*5*3*3}{2*5*3*5}$= $\frac{3}{2}$

d) $\frac{26-2}{90} * \frac{100}{8*8}$ = $\frac{3*8*10*10}{9*10*8*8}$= $\frac{5}{12}$