Question

ex 6 va rog frumos....

Answer 1

a)-1 intreg1/8•(15/36-7/9-3/4)-(-0,5)^2=
=-9/8•(15-7•4-3•9)/36-0,25=
simplificăm 9 si 36 prin 9
=-1/8•(15-28-27)/4-25/100=
=-1/8+(15-55)/4-1/4=
=-1/8-40/4-1/4=
=-1/8-10-1/4=
=-10+(-1-1•2)/8=
=-10-3/8=-10întregi 3/8

b)-0,(3):(17/42-5/7+9/14)+(1/5)^-1=
=-3/9:(17-5•6+9•3)/42+5=
=-1/3•42/(17-30+27)+5=
=-1/3•42/14+5=
=-1/3•3+5=
=-1+5=4

c)[1/3(10-1/4)-3 intregi2/5]:(-1 întreg 1/5)=
=(1/3•9 întregi 3/4-(3•5+2)/5):6/5=
=(1/3•39/4-17/5):6/5=
simplificăm 3 și 39 prin 3
=(13/4-17/5)•5/6=
=(13•5-17•4)/20•5/6=
=(65-68)/20•5/6=
=-3/20•5/6=
=(-3•5)/(20•6)=
=-15/120=
=-3/40

d)(1 intreg3/10:2 intregi3/5):(2 intregi1/2-1 intreg2/3:3 intregi1/3+1 intreg1/4)=
=(13/10-13/5):(5/2-5/3:10/3+5/4=
=((13-13•2)/10):(5/2-5/3•3/10+5/4=
=((13-26)/10):(5/2-5/10+5/4)=
=-13/10:(5/2-1/2+5/4)=
=-13/10:(4/2+5/4)=
=-13/10:(2+5/4)=
=-13/10:13/4=
=-13/10•4/13=
=-4/10=
=-2/5