Question

ex 6 va rogggggfrumosssssssss dau 100 puncte

Answer 1

Răspuns:

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Answer 2

Răspuns:

Explicație pas cu pas:

$a)~\bigg(\dfrac{4}{7} \bigg)^{9}:\bigg(\dfrac{4}{7} \bigg)^{5}=\bigg(\dfrac{4}{7} \bigg)^{9-5}=\red{\bigg(\dfrac{4}{7} \bigg)^{4}}$

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$b)~\bigg(\dfrac{3}{18} \bigg)^{17}:\bigg(\dfrac{3}{18} \bigg)^{1}=\bigg(\dfrac{3}{18} \bigg)^{17-1}=\bigg(\dfrac{3^{(3}~}{18} \bigg)^{16}=\purple{\bigg(\dfrac{1}{6} \bigg)^{16}}$

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$c)~\bigg(\dfrac{2}{11} \bigg)^{23}:\bigg(\dfrac{2}{11} \bigg)^{15}=\bigg(\dfrac{2}{11} \bigg)^{23-15}=\blue{\bigg(\dfrac{2}{11} \bigg)^{8}}$

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$d)~\bigg(2\dfrac{3}{5} \bigg)^{31}:\bigg(2\dfrac{3}{5} \bigg)^{18}:\bigg(2\dfrac{3}{5} \bigg)^{6}=\bigg(2\dfrac{3}{5} \bigg)^{31-18-6}=\green{\bigg(2\dfrac{3}{5} \bigg)^{7}}$

⋆ Formule pentru puteri:

$\red{ \bf a^{0} = 1}$

$\red{\bf (a^{n})^{m} = a^{n \cdot m}}$

$\red{\bf a^{n}\cdot a^{m} =a^{n+m}}$

$\red{ \bf a^{n}: a^{m} =a^{n-m}}$