Matematică, întrebare adresată de razvanmesina04, 8 ani în urmă

ex 6 va rogggggfrumosssssssss dau 100 puncte

Anexe:

Răspunsuri la întrebare

Răspuns de Maas10
4

Răspuns:

.........................

Anexe:

Damaya: perfect
razvanmesina04: ms
Răspuns de pav38
6

Răspuns:

Explicație pas cu pas:

a)~\bigg(\dfrac{4}{7} \bigg)^{9}:\bigg(\dfrac{4}{7} \bigg)^{5}=\bigg(\dfrac{4}{7} \bigg)^{9-5}=\red{\bigg(\dfrac{4}{7} \bigg)^{4}}

---------------------------------------------------

b)~\bigg(\dfrac{3}{18} \bigg)^{17}:\bigg(\dfrac{3}{18} \bigg)^{1}=\bigg(\dfrac{3}{18} \bigg)^{17-1}=\bigg(\dfrac{3^{(3}~}{18} \bigg)^{16}=\purple{\bigg(\dfrac{1}{6} \bigg)^{16}}

---------------------------------------------------

c)~\bigg(\dfrac{2}{11} \bigg)^{23}:\bigg(\dfrac{2}{11} \bigg)^{15}=\bigg(\dfrac{2}{11} \bigg)^{23-15}=\blue{\bigg(\dfrac{2}{11} \bigg)^{8}}

---------------------------------------------------

d)~\bigg(2\dfrac{3}{5} \bigg)^{31}:\bigg(2\dfrac{3}{5} \bigg)^{18}:\bigg(2\dfrac{3}{5} \bigg)^{6}=\bigg(2\dfrac{3}{5} \bigg)^{31-18-6}=\green{\bigg(2\dfrac{3}{5}  \bigg)^{7}}

Formule pentru puteri:

\red{ \bf a^{0} = 1}

\red{\bf (a^{n})^{m} = a^{n \cdot m}}

\red{\bf a^{n}\cdot a^{m} =a^{n+m}}

\red{ \bf a^{n}: a^{m} =a^{n-m}}

Alte întrebări interesante