Question

ex 7 : Calculați:
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Answer 1

$a)3 \sqrt{2} \times 4 \sqrt{3} = 3 \times 4 \sqrt{2 \times 3} = 3 \times 4 \sqrt{6} = 12 \sqrt{6} \\ \\ b) - 2 \sqrt{7} \times 5 \sqrt{2} = - 2 \times 5 \sqrt{7 \times 2} = - 2 \times 5 \sqrt{14} = - 10 \sqrt{14} \\ \\ c)6 \sqrt{6} \times \sqrt{5} = 6 \sqrt{6 \times 5} = 6 \sqrt{30} \\ \\ f)8 \sqrt{18} : \sqrt{6} = 8 \times 3 \sqrt{2} : \sqrt{6} = 24 \sqrt{2} : \sqrt{6} = 24 \sqrt{2} \times \frac{1}{ \sqrt{6} } = \frac{24 \sqrt{2} \sqrt{6} }{6} = \frac{24 \sqrt{12} }{6} = \frac{24 \times 2 \sqrt{3} }{6} = \frac{48 \sqrt{3} }{6} = 8 \sqrt{3}$