Question

ex 7 rpd dau coroana

Answer 1

Bună!

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$^{\sqrt{3}) } \frac{4-3\sqrt{6} }{2\sqrt{3} } -^{\sqrt{3}) } \frac{3\sqrt{6} -2}{3\sqrt{3} } +^{\sqrt{3} )} \frac{3+2\sqrt{6} }{4\sqrt{3} }=$

$=\frac{4\sqrt{3} -9\sqrt{2} }{6} -\frac{9\sqrt{2} -2\sqrt{3} }{9} +\frac{3\sqrt{3} +6\sqrt{2} }{12}=$

$=\frac{4\sqrt{3} -9\sqrt{2} }{6} -\frac{9\sqrt{2} -2\sqrt{3} }{9} +\frac{3(\sqrt{3} +2\sqrt{2}) }{12}=$

$=^{6)} \frac{4\sqrt{3} -9\sqrt{2} }{6} -^{4)} \frac{9\sqrt{2} -2\sqrt{3} }{9} +^{9)} \frac{\sqrt{3} +2\sqrt{2} }{4} =$

$= \frac{24\sqrt{3}-54\sqrt{2} -36\sqrt{2}+8\sqrt{3} +9\sqrt{3}+18\sqrt{2} }{36} =$

$=\frac{41\sqrt{3}-72\sqrt{2} }{36}$

**

$3\sqrt{18} =3\sqrt{3^{2}*2 } =3*3\sqrt{2} =9\sqrt{2}$

$2\sqrt{18} =2\sqrt{3^{2}*2 } =2*3\sqrt{2} =6\sqrt{2}$