Question

Ex.9 pag.35
Efectueaza in doua moduri:

a)5x(5+2)
8x(6-3)
(2+4)x9
(5-3)x6
(3+2+4)x10
(5+1+2)x9
8x(7-3)
10x(4+3-2)

Vreau doar al doilea mod pls

Answer 1

5x(5+2)=5x7=35 (primul mod)
5x5+5x2=25+10=35 (al doilea mod)

8x(6-3)=8x6-8x3=48-24=24

(2+4)x9=2x9+4x9=18+36=54
(5-3)x6=5x6-3x6=30-18=12
(3+2+4)x10=3x10+2x10+4x10=30+20+40=90
(5+1+2)x9=5x9+1x9+2x9=45+9+18=72
8x(7-3)=8x7-8x3=56-24=32
10x(4+3-2)=10x4+10x3-10x2=40+30-20=50