Question

Ex 9 vă rog, îmi trb urgent

Answer 1

Vs1 = 200cm^3 sol. H2SO4
C1 = 98%
ro1 = 1,84g/cm^3
Vs2 = 250cm^3 sol. H2SO4
C2 = 1M
m H2O ad = 150g
C = 2M sol. NaOH

ro1 = ms1/Vs1 => ms1 = 1,84×200 = 368g sol. H2SO4
C1 = md1/ms1×100 => md1 = 98×368/100 = 360,64g H2SO4

C2 = md2/M×Vs(L) => md2 = 1×98×0,25 = 24,5g H2SO4

md final = 360,64+24,5 = 385,14g H2SO4
Vs final = 200+250+150(VH2O) = 600cm^3 = 0,6L

a) Cf = mdf/M×Vsf = 385,14/98×0,6 = 6,55M

b) n H2SO4 final = 385,14/98 = 3,93 moli

2NaOH + H2SO4 => Na2SO4 + 2H2O

2 moli NaOH........1 mol H2SO4
x moli NaOH.......3,93 moli Na2SO4

x = 7,86 moli NaOH

C = n/Vs => Vs = n/C = 7,86/2 = 3,93 L sol. NaOH