Question

Ex. De la teza la puterea
512 la 4 × 8 la 5 × 32 la 8

Answer 1

512^4 × 8^5 × 32^8=
=(2^9)^4 × (2^3)^5 × (2^5)^8=
=2^36 × 2^15 × 2^40=
=2^91

Answer 2

512^4×8^5×32^8=(2^9)^4×(2^3)^5×(2^5)^8=2^36×2^15×2^40=2^36+15+40=2^91