Question

Ex K si L VA ROG DAU COROANA!

Answer 1

k)
48:4+{12+[60:5-(12:a+5):3]:5}:7=14
12+{12+[12-(12:a+5):3]:5}:7=14
{12+[12-(12:a+5):3]:5}:7=14-12
{12+[12-(12:a+5):3]:5}:7=2
12+[12-(12:a+5):3]:5=2×7
12+[12-(12:a+5):3]:5=14
[12-(12:a+5):3]:5=14-12
[12-(12:a+5):3]:5=2
12-(12:a+5):3=2×5
12-(12:a+5):3=10
(12:a+5):3=12-10
(12:a+5):3=2
12:a+5=2×3
12:a+5=6
12:a=6-5
12:a=1
a=12:1
a=12

PROBA :

48:4+{12+[60:5-(12:a+5):3]:5}:7=14

vom inlocui pe a cu 12 sa vedem daca rezultatul ne dă 14 =>

48:4+{12+[60:5-(12:12+5):3]:5}:7=
=12+{12+[12-(1+5):3]:5}:7=
=12+[12+(12-6:3):5]:7=
=12+[12+(12-2):5]:7=
=12+(12+10:5):7=
=12+(12+2):7=
=12+14:7=
=12+2=
=15 (adevarat )



l)
{[(5a+5)×5+5]×5+5}×5+5=1405
{[(5a+5)×5+5]×5+5}×5=1405-5
{[(5a+5)×5+5]×5+5}×5=1400
[(5a+5)×5+5]×5+5=1400:5
[(5a+5)×5+5]×5+5=280
[(5a+5)×5+5]×5=280-5
[(5a+5)×5+5]×5=275
(5a+5)×5+5=275:5
(5a+5)×5+5=55
(5a+5)×5=55-5
(5a+5)×5=50
5a+5=50:5
5a+5=10
5a=10-5
5a=5
a=5:5
a=1


PROBA :
înlocuim pe a cu 1 =>

{[(5×1+5)×5+5]×5+5}×5+5=
={[(5+5)×5+5]×5+5}×5+5=
=[(10×5+5)×5+5]×5+5=
=[(50+5)×5+5]×5+5=
=(55×5+5)×5+5=
=(275+5)×5+5=
=280×5+5=
=1400+5=
=1405 (adevarat )