Question

Ex nr 13,14,15 daca stie cineva sa ma ajute

Answer 1

13.a=24x+16=8(3x+2)
=>restul e 0
a=8(3x+2)=4*2*(3x+2)=4(6x+4)
=>restul e 0
14.a=29x+7
a=3(7x+2)+1
=>restul impartirii lui a la 3este 1
b)a=28x+7=7(4x+1)
=>restul e 0
15.1*2*3*..*28+20=1*2*3*4*..*16*17*...*28+20=17(1*2*3*..*15*16*18*19*...* 28+17+3=17(1*2*3*...*16*18*19*...*28+1)+3
=>restul e 3